How to Generate Random Colors Programmatically
Creating random colors is actually more difficult than it seems. The randomness itself is easy, but aesthetically pleasing randomness is more difficult. For a little project at work I needed to automatically generate multiple background colors with the following properties:
- Text over the colored background should be easily readable
- Colors should be very distinct
- The number of required colors is not initially known
Naïve Approach
The first and simplest approach is to create random colors by simply using a random number between [0, 256[ for the R, G, B values. I have created a little Ruby script to generate sample HTML code:
# generates HTML code for 26 background colors given R, G, B values.
def gen_html
('A'..'Z').each do |c|
r, g, b = yield
printf "<span style=\"background-color:#%02x%02x%02x; padding:5px; -moz-border-radius:3px; -webkit-border-radius:3px;\">#{c}</span> ", r, g, b
end
end
# naive approach: generate purely random colors
gen_html { [rand(256), rand(256), rand(256)] }
The generated output looks like this:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
As you can see this is quite suboptimal. Some letters are hard to read because the background is too dark (B, Q, S), other colors look very similar (F, R).
Using HSV Color Space
Let's fix the too dark / too bright problem first. A convenient way to do this is to not use the RGB color space, but HSV (Hue, Saturation, Value). Here you get equally bright and colorful colors by using a fixed value for saturation and value, and just modifying the hue.
Based on the description provided by the wikipedia article on conversion from HSV to RGB I have implemented a converter:
# HSV values in [0..1[ # returns [r, g, b] values from 0 to 255 def hsv_to_rgb(h, s, v) h_i = (h*6).to_i f = h*6 - h_i p = v * (1 - s) q = v * (1 - f*s) t = v * (1 - (1 - f) * s) r, g, b = v, t, p if h_i==0 r, g, b = q, v, p if h_i==1 r, g, b = p, v, t if h_i==2 r, g, b = p, q, v if h_i==3 r, g, b = t, p, v if h_i==4 r, g, b = v, p, q if h_i==5 [(r*256).to_i, (g*256).to_i, (b*256).to_i] end
Using the generator and fixed values for saturation and value:
# using HSV with variable hue
gen_html { hsv_to_rgb(rand, 0.5, 0.95) }
returns something like this:
Much better. The text is easily readable, and all colors have a similar brightness. Unfortunately, since we have limited us to less colors now, the difference between the randomly generated colors is even less than in the first approach.
Golden Ratio
Using just rand() to choose different values for hue does not lead to a good use of the whole color spectrum, it simply is too random.

Here I have generated 2, 4, 8, 16, and 32 random values and printed them all on a scale. Its easy to see that some values are very tightly packed together, which we do not want.
Lo and behold, some mathematician has discovered the Golden Ratio more than 2400 years ago. It has lots of interesting properties, but for us only one is interesting:
[...] Furthermore, it is a property of the golden ratio, Φ, that each subsequent hash value divides the interval into which it falls according to the golden ratio!
-- Bruno R. Preiss, P.Eng.
Using the golden ratio as the spacing, the generated values look like this:

Much better! The values are very evenly distributed, regardless how many values are used. Also, the algorithm for this is extremly simple. Just add 1/Φ and modulo 1 for each subsequent color.
# use golden ratio
golden_ratio_conjugate = 0.618033988749895
h = rand # use random start value
gen_html {
h += golden_ratio_conjugate
h %= 1
hsv_to_rgb(h, 0.5, 0.95)
}
The final result:
You can see that the first few values are very different, and the difference decreases as more colors are added (Z and E are already quite similar). Anyways, this is good enough for me.
And because it is so beautiful, here are some more colors ![]()
s=0.99, v=0.99, s=0.25, h=0.8, and s=0.3, v=0.99
Have fun!
Martin
6 Responses to “How to Generate Random Colors Programmatically”
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Nice explanation Martin! I have done something very similar in a ColorUtils for Java. I find it’s an interesting but very subjective matter and for many practical uses, you will want to seed the algorithm with avoidable colors.
I attacked the problem looking at the color space as a HSV cone, placing points as far away from another in a 3D space (and often seeding the algorithm with the color black and white).
I wrote a short method that given a background color will tell you whether or not white or black text will be the most readable. Using this you can still use saturated colors.
You can find it here:
http://blog.nitriq.com/BlackVsWhiteText.aspx
@jon, nice article with calculating white vs. black text! then you have a wider range of colors to choose from. but I have not yet thought about how to select distinct colors when you can change more than just the hue parameter.
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Is it safe to assume that you used the golden ratio approach instead of a perfectly even distribution because it was quicker to implement and not far from ideal anyway?
Hello Brian, no, I cannot use a perfectly even distribution because I do not know how many colors I need in advance. I simply pick colors one after the other, and do not change already picked colors. As far as I can tell the golden ratio is the optimal way for this use case.